← Complete problem index

PROJECT EULER · #0050

Consecutive Prime Sum

Statement only · SolvedOriginal problem ↗

The prime 41, can be written as the sum of six consecutive primes:

41=2+3+5+7+11+13.

This is the longest sum of consecutive primes that adds to a prime below one-hundred.

The longest sum of consecutive primes below one-thousand that adds to a prime, contains 21 terms, and is equal to 953.

Which prime, below one-million, can be written as the sum of the most consecutive primes?

Write-up coming later

The complete problem is available here. An approach, code, and answer will be added later.