Cyclic equation

The equation $x\times y+y\times z+z\times x=n$ with $0<x\le y\le z$ has $11$ solutions for $n=1234$:

• $1\times 4+4\times 246+246\times 1=1234$
• $1\times 12+12\times 94+94\times 1=1234$
• $1\times 18+18\times 64+64\times 1=1234$
• $3\times 8+8\times 110+110\times 3=1234$
• $4\times 6+6\times 121+121\times 4=1234$
• $4\times 21+21\times 46+46\times 4=1234$
• $8\times 14+14\times 51+51\times 8=1234$
• $10\times 13+13\times 48+48\times 10=1234$
• $10\times 19+19\times 36+36\times 10=1234$
• $12\times 14+14\times 41+41\times 12=1234$
• $18\times 20+20\times 23+23\times 18=1234$

How many solutions are there for $n=3000000$ ?

Answer format: $count,\sum x,\sum y,\sum z$

Example: 11,72,149,880 for n = 1234

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