A number consisting entirely of ones is called a repunit. We shall define $R(k)$ to be a repunit of length $k$; for example, $R(6)=111111$.

Let us consider repunits of the form $R({10}^n)$.

Although $R(10)$, $R(100)$, or $R(1000)$ are not divisible by $17$, $R(10000)$ is divisible by $17$. Yet there is no value of $n$ for which $R({10}^n)$ will divide by $19$. In fact, it is remarkable that $11$, $17$, $41$, and $73$ are the only four primes below one-hundred that can be a factor of $R({10}^n)$.

Find the sum of all the primes below one-hundred thousand that will never be a factor of $R({10}^n)$.