We call the convex area enclosed by two circles a lenticular hole if:

• The centres of both circles are on lattice points.
• The two circles intersect at two distinct lattice points.
• The interior of the convex area enclosed by both circles does not contain any lattice points.

Consider the circles:
$C_0$: $x^2+y^2=25$
$C_1$: $(x+4{)}^2+(y-4{)}^2=1$
$C_2$: $(x-12{)}^2+(y-4{)}^2=65$

The circles $C_0$, $C_1$ and $C_2$ are drawn in the picture below.

$C_0$ and $C_1$ form a lenticular hole, as well as $C_0$ and $C_2$.

We call an ordered pair of positive real numbers $(r_1,r_2)$ a lenticular pair if there exist two circles with radii $r_1$ and $r_2$ that form a lenticular hole. We can verify that $(1,5)$ and $(5,\sqrt{65})$ are the lenticular pairs of the example above.

Let $L(N)$ be the number of distinct lenticular pairs $(r_1,r_2)$ for which $0<r_1\le r_2\le N$.
We can verify that $L(10)=30$ and $L(100)=3442$.

Find $L(100000)$.