Nim is a game played with heaps of stones, where two players take it in turn to remove any number of stones from any heap until no stones remain.

We'll consider the three-heap normal-play version of Nim, which works as follows:

• At the start of the game there are three heaps of stones.
• On each player's turn, the player may remove any positive number of stones from any single heap.
• The first player unable to move (because no stones remain) loses.

If $(n_1,n_2,n_3)$ indicates a Nim position consisting of heaps of size $n_1$, $n_2$, and $n_3$, then there is a simple function, which you may look up or attempt to deduce for yourself, $X(n_1,n_2,n_3)$ that returns:

• zero if, with perfect strategy, the player about to move will eventually lose; or
• non-zero if, with perfect strategy, the player about to move will eventually win.

For example $X(1,2,3)=0$ because, no matter what the current player does, the opponent can respond with a move that leaves two heaps of equal size, at which point every move by the current player can be mirrored by the opponent until no stones remain; so the current player loses. To illustrate:

• current player moves to $(1,2,1)$
• opponent moves to $(1,0,1)$
• current player moves to $(0,0,1)$
• opponent moves to $(0,0,0)$, and so wins.

For how many positive integers $n\hspace{0.17em}\le \hspace{0.17em}{2}^{30}$ does $X(n,2n,3n)=0$ ?