We define a simber to be a positive integer in which any odd digit, if present, occurs an odd number of times, and any even digit, if present, occurs an even number of times.

For example, $141221242$ is a $9$-digit simber because it has three $1$'s, four $2$'s and two $4$'s.

Let $Q(n)$ be the count of all simbers with at most $n$ digits.

You are given $Q(7)=287975$ and $Q(100)mod1000000123=123864868$.

Find $(\sum _{1\le u\le 39}Q(2^u))mod1000000123$.