The McCarthy 91 function is defined as follows: $$M_{91}(n)=\{\begin{array}{ll}n-10& \text{if }n>100\\ M_{91}(M_{91}(n+11))& \text{if }0\le n\le 100\end{array}$$

We can generalize this definition by abstracting away the constants into new variables: $$M_{m,k,s}(n)=\{\begin{array}{ll}n-s& \text{if }n>m\\ M_{m,k,s}(M_{m,k,s}(n+k))& \text{if }0\le n\le m\end{array}$$

This way, we have $M_{91}=M_{100,11,10}$.

Let $F_{m,k,s}$ be the set of fixed points of $M_{m,k,s}$. That is, $$F_{m,k,s}=\{n\in \mathbb{N}|M_{m,k,s}(n)=n\}$$

For example, the only fixed point of $M_{91}$ is $n=91$. In other words, $F_{100,11,10}=\{91\}$.

Now, define $SF(m,k,s)$ as the sum of the elements in $F_{m,k,s}$ and let $S(p,m)={\displaystyle \sum _{1\le s<k\le p}SF(m,k,s)}$.

For example, $S(10,10)=225$ and $S(1000,1000)=208724467$.

Find $S({10}^6,{10}^6)$.