Two cars are on a circular track of total length $2n$, facing the same direction, initially distance $n$ apart.
They move in turn. At each turn, the moving car will advance a distance of $1$, $2$ or $3$, with equal probabilities.
The chase ends when the moving car reaches or goes beyond the position of the other car. The moving car is declared the winner.

Let $S(n)$ be the difference between the winning probabilities of the two cars.
For example, when $n=2$, the winning probabilities of the two cars are $\frac{9}{11}$ and $\frac{2}{11}$, and thus $S(2)=\frac{7}{11}$.

Let ${\displaystyle T(N)=\sum _{n=2}^{N}S(n)}$.

You are given that $T(10)=2.38235282$ rounded to 8 digits after the decimal point.

Find $T({10}^{14})$, rounded to 8 digits after the decimal point.